Other comparison operators

A binary comparison operator compares two variables or quantities. Note that integer and string comparison use a different set of operators.

Integer comparison

-eq

Is equal to

if [ "$a" -eq "$b" ]
-ne

Is no equal to

if [ "$a" -ne "$b" ]
-gt

Is greater than to

if [ "$a" -gt "$b" ]
-ge

Is greater than or equal to

if [ "$a" -ge "$b" ]
-lt

Is less than to

if [ "$a" -lt "$b" ]
-le

Is less than or equal to

if [ "$a" -le "$b" ]
<

Is less than (within double parentheses)

(( "$a" < "$b" ))
<=

Is less than or equal to (within double parentheses)

(( "$a" <= "$b" ))
>

Is greater than (within double parentheses)

(( "$a" > "$b" ))
>=

Is greater than or equal to (within double parentheses)

(( "$a" >= "$b" ))

String comparison

=

Is equal to

if [ "$a" = "$b" ]

Caution: Note the whitespace framing the =!

if [ "$a"="$b" ] is not equivalent to the above.

==

Is equal to

if [ "$a" == "$b" ]

This is a synonym for =.

Note: The == comparison operator behaves differently within a double-brackets test than within single brackets.

[[ $a == z* ]] # True if $a starts with an "z" (pattern matching). [[ $a == "z*" ]] # True if $a is equal to z* (literal matching).

[ $a == z* ] # File globbing and word splitting take place. [ "$a" == "z*" ] # True if $a is equal to z* (literal matching).

# Thanks, Stéphane Chazelas

!=

Is not equal to

if [ "$a" != "$b" ]

This operator uses pattern matching within a [[ ... ]] construct.

<

Is less than in ASCII alphabetical order

if [[ "$a" < "$b" ]]

if [ "$a" \< "$b" ]

Note that the < needs to be escaped within a [ ] construct.

>

Is greater than in ASCII alphabetical order

if [[ "$a" > "$b" ]]

if [ "$a" \> "$b" ]

Note that the > needs to be escaped within a [ ] construct.

TODO: See example for an application of this operator

-z

String is null, that is, has zero length

String='' # Zero-length ("null") string variable.

if [ -z "$String" ] then echo "\$String is null." else echo "\$String is NOT null." fi # $String is null.

-n

String is not null

Caution: The -n test requires that the string be quoted within the test brackets. Using an unquoted string with ! -z, or even just the unquoted string alone within test brackets (see Example 7-6) normally works, however, this is an unsafe practice. Always quote a tested string. [1]

Testing whether a string is null

#!/bin/bash # str-test.sh: Testing null strings and unquoted strings, #+ but not strings and sealing wax, not to mention cabbages and kings . . .

# Using if [ ... ]

# If a string has not been initialized, it has no defined value. # This state is called "null" (not the same as zero!).

if [ -n $string1 ] # string1 has not been declared or initialized. then echo "String \"string1\" is not null." else echo "String \"string1\" is null." fi # Wrong result. # Shows $string1 as not null, although it was not initialized.

echo

# Let's try it again.

if [ -n "$string1" ] # This time, $string1 is quoted. then echo "String \"string1\" is not null." else echo "String \"string1\" is null." fi # Quote strings within test brackets!

echo

if [ $string1 ] # This time, $string1 stands naked. then echo "String \"string1\" is not null." else echo "String \"string1\" is null." fi # This works fine. # The [ ... ] test operator alone detects whether the string is null. # However it is good practice to quote it (if [ "$string1" ]). # # As Stephane Chazelas points out, # if [ $string1 ] has one argument, "]" # if [ "$string1" ] has two arguments, the empty "$string1" and "]"

echo

string1=initialized

if [ $string1 ] # Again, $string1 stands unquoted. then echo "String \"string1\" is not null." else echo "String \"string1\" is null." fi # Again, gives correct result. # Still, it is better to quote it ("$string1"), because . . .

string1="a = b"

if [ $string1 ] # Again, $string1 stands unquoted. then echo "String \"string1\" is not null." else echo "String \"string1\" is null." fi # Not quoting "$string1" now gives wrong result!

exit 0 # Thank you, also, Florian Wisser, for the "heads-up".

zmore

#!/bin/bash # zmore

# View gzipped files with 'more' filter.

E_NOARGS=85 E_NOTFOUND=86 E_NOTGZIP=87

if [ $# -eq 0 ] # same effect as: if [ -z "$1" ] # $1 can exist, but be empty: zmore "" arg2 arg3 then echo "Usage: `basename $0` filename" >&2 # Error message to stderr. exit $E_NOARGS # Returns 85 as exit status of script (error code). fi

filename=$1

if [ ! -f "$filename" ] # Quoting $filename allows for possible spaces. then echo "File $filename not found!" >&2 # Error message to stderr. exit $E_NOTFOUND fi

if [ ${filename##*.} != "gz" ] # Using bracket in variable substitution. then echo "File $1 is not a gzipped file!" exit $E_NOTGZIP fi

zcat $1 | more

# Uses the 'more' filter. # May substitute 'less' if desired.

exit $? # Script returns exit status of pipe. # Actually "exit $?" is unnecessary, as the script will, in any case, #+ return the exit status of the last command executed.

Compound Comparison

-a

Logical and

exp1 -a exp2 returns true if both exp1 and exp2 are true.

-o

Logical or

exp1 -o exp2 returns true if either exp1 or exp2 is true.

These are similar to the Bash comparison operators && and ||, used within double brackets.

[[ condition1 && condition2 ]]

The -o and -a operators work with the test command or occur within single test brackets.

if [ "$expr1" -a "$expr2" ]
then
  echo "Both expr1 and expr2 are true."
else
  echo "Either expr1 or expr2 is false."
fi

Caution: But, as rihad points out:

[ 1 -eq 1 ] && [ -n "`echo true 1>&2`" ] # true [ 1 -eq 2 ] && [ -n "`echo true 1>&2`" ] # (no output) # ^^^^^^^ False condition. So far, everything as expected.

# However ... [ 1 -eq 2 -a -n "`echo true 1>&2`" ] # true # ^^^^^^^ False condition. So, why "true" output?

# Is it because both condition clauses within brackets evaluate? [[ 1 -eq 2 && -n "`echo true 1>&2`" ]] # (no output) # No, that's not it.

# Apparently && and || "short-circuit" while -a and -o do not.

TODO: Refer to Example 8-3, Example 27-17, and Example A-29 to see compound comparison operators in action.

[1]As S.C. points out, in a compound test, even quoting the string variable might not suffice. [ -n "$string" -o "$a" = "$b" ] may cause an error with some versions of Bash if $string is empty. The safe way is to append an extra character to possibly empty variables, [ "x$string" != x -o "x$a" = "x$b" ] (the "x's" cancel out).